MODEL:
! Machine repair model;
SETS:
NREP/1..5/: ! Consider 5 possible repair persons;
NDOWN, ! Expected no. of down machines;
CPERHR,! Expected cost/hour of down machines;
TCOST; ! Total expected cost/hour;
ENDSETS
! The input data;
NMACH = 10;! No. machines subject to breakdown;
RTIME = 1; ! Average repair time;
UPTIME = 5;! Mean time between failures;
CR = 30; ! Hourly cost of a repair person;
CM = 350; ! Hourly cost of a down machine;
! The machine repairman queuing model;
! For each case of 1  5 service people calculate
expected number of machines down, cost per hour
of down machines, and total cost per hour of
operations. @PFS calculates the Probability in
a Finite Source, in this case expected number of
machines under repair. ;
@FOR( NREP( I):
NDOWN( I) =
CPERHR( I) = CM * NDOWN( I);
TCOST( I) = CPERHR( I) + CR * I
);
END
